7sin^2(2x+3)+sin(2x+3)-2=0

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Solution for 7sin^2(2x+3)+sin(2x+3)-2=0 equation:


Simplifying
7sin2(2x + 3) + sin(2x + 3) + -2 = 0

Reorder the terms:
7in2s(3 + 2x) + sin(2x + 3) + -2 = 0
(3 * 7in2s + 2x * 7in2s) + sin(2x + 3) + -2 = 0
(21in2s + 14in2sx) + sin(2x + 3) + -2 = 0

Reorder the terms:
21in2s + 14in2sx + ins(3 + 2x) + -2 = 0
21in2s + 14in2sx + (3 * ins + 2x * ins) + -2 = 0
21in2s + 14in2sx + (3ins + 2insx) + -2 = 0

Reorder the terms:
-2 + 3ins + 2insx + 21in2s + 14in2sx = 0

Solving
-2 + 3ins + 2insx + 21in2s + 14in2sx = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 3ins + 2insx + 21in2s + 2 + 14in2sx = 0 + 2

Reorder the terms:
-2 + 2 + 3ins + 2insx + 21in2s + 14in2sx = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 3ins + 2insx + 21in2s + 14in2sx = 0 + 2
3ins + 2insx + 21in2s + 14in2sx = 0 + 2

Combine like terms: 0 + 2 = 2
3ins + 2insx + 21in2s + 14in2sx = 2

Reorder the terms:
-2 + 3ins + 2insx + 21in2s + 14in2sx = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 3ins + 2insx + 21in2s + 14in2sx = 0

The solution to this equation could not be determined.

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